To find the coordinates of point \( X \) that divides segment \( AB \) in the ratio \( AX:BX = 1:2 \), we can use the section formula.
Let the coordinates of point \( A \) be \( (x_1, y_1) \) and those of point \( B \) be \( (x_2, y_2) \). The coordinates of the dividing point \( X \) can be calculated as:
\[ X = \left( \frac{mx_2 + nx_1}{m+n}, \frac{my_2 + ny_1}{m+n} \right) \]
where \( m = 2 \) and \( n = 1 \) (since \( AX:BX = 1:2 \)), which means:
\[ X = \left( \frac{2x_2 + 1x_1}{2 + 1}, \frac{2y_2 + 1y_1}{2 + 1} \right) = \left( \frac{2x_2 + x_1}{3}, \frac{2y_2 + y_1}{3} \right) \]
If the coordinates of point \( A \) and \( B \) are given in the image (which you mentioned but cannot provide here), please input the coordinates for \( A \) and \( B \), and I will calculate the coordinates for \( X \).
Let me know the specific coordinates for points \( A \) and \( B \), and I will help you find \( X \).