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Question

David rolls a die and spins the spinner.

6-sided die and 4-section spinner, numbered 1, 2, 3, and 4 are shown.

What is the probability that he gets a 1 on both the die and the spinner?

(1 point)
Responses

15

1 5

512

5 12

112

1 12

124

1 24

Answer 1

To find the probability of getting a 1 on both the die and the spinner, we need to calculate the individual probabilities and then combine them.

1. Probability of rolling a 1 on the die:

   • A 6-sided die has the numbers 1 through 6. The probability of rolling a 1 is: \[ P(\text{1 on die}) = \frac{1}{6} \]

2. Probability of spinning a 1 on the spinner:

   • A spinner with 4 sections numbered 1 through 4 has a probability of: \[ P(\text{1 on spinner}) = \frac{1}{4} \]

3. Combined probability of both events occurring: Since the two events (rolling the die and spinning the spinner) are independent, we multiply the probabilities together: \[ P(\text{1 on die and 1 on spinner}) = P(\text{1 on die}) \times P(\text{1 on spinner}) = \frac{1}{6} \times \frac{1}{4} \] \[ P(\text{1 on die and 1 on spinner}) = \frac{1}{24} \]

Thus, the probability that David gets a 1 on both the die and the spinner is \( \frac{1}{24} \).

The correct response is: 124 \( \frac{1}{24} \)