To find the probability that David rolls a 1 on a die and gets a 1 on a spinner, we need to consider the probabilities of each event separately.
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Probability of rolling a 1 on a die: A standard die has 6 faces. The probability of rolling a 1 is: \[ P(\text{1 on die}) = \frac{1}{6} \]
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Probability of spinning a 1 on the spinner: Typically, spinners can have varying numbers of sections. Assuming the spinner has 6 equal sections and the outcome of spinning a 1 is one of those sections, the probability of this event is: \[ P(\text{1 on spinner}) = \frac{1}{6} \]
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Combined Probability: Since the die roll and spinner spin are independent events, the combined probability is the product of the individual probabilities: \[ P(\text{1 on die and 1 on spinner}) = P(\text{1 on die}) \times P(\text{1 on spinner}) = \frac{1}{6} \times \frac{1}{6} = \frac{1}{36} \]
Now looking through your response options, it seems there might not be an exact match with \(\frac{1}{36}\). Please double-check whether there is any additional context or if the spinner has a different number of sections that might change the probability.
If the spinner has 12 sections and only one with a "1", then: \[ P(\text{1 on spinner}) = \frac{1}{12} \] In that case, the combined probability would be: \[ P(\text{1 on die and 1 on spinner}) = \frac{1}{6} \times \frac{1}{12} = \frac{1}{72} \] Which also isn't an option.
Make sure to verify the setup, specifically how many sections are on the spinner, before selecting a final response!