Question

Use the image to answer the question. David rolls a die and spins the spinner. What is the probability that he gets a 1 on both the die and the spinner? (1 point) Responses 15 1 5 512 5 12 112 1 12 124

Answer 1

To find the probability that David rolls a 1 on a die and gets a 1 on a spinner, we need to consider the probabilities of each event separately.

1. **Probability of rolling a 1 on a die**: A standard die has 6 faces. The probability of rolling a 1 is:
\[
P(\text{1 on die}) = \frac{1}{6}
\]

2. **Probability of spinning a 1 on the spinner**: Typically, spinners can have varying numbers of sections. Assuming the spinner has 6 equal sections and the outcome of spinning a 1 is one of those sections, the probability of this event is:
\[
P(\text{1 on spinner}) = \frac{1}{6}
\]

3. **Combined Probability**: Since the die roll and spinner spin are independent events, the combined probability is the product of the individual probabilities:
\[
P(\text{1 on die and 1 on spinner}) = P(\text{1 on die}) \times P(\text{1 on spinner}) = \frac{1}{6} \times \frac{1}{6} = \frac{1}{36}
\]

Now looking through your response options, it seems there might not be an exact match with \(\frac{1}{36}\). Please double-check whether there is any additional context or if the spinner has a different number of sections that might change the probability.

If the spinner has 12 sections and only one with a "1", then:
\[
P(\text{1 on spinner}) = \frac{1}{12}
\]
In that case, the combined probability would be:
\[
P(\text{1 on die and 1 on spinner}) = \frac{1}{6} \times \frac{1}{12} = \frac{1}{72}
\]
Which also isn't an option.

Make sure to verify the setup, specifically how many sections are on the spinner, before selecting a final response!