To analyze the equation \( m(p) = 20(2^p) \), we need to consider both the range and the behavior of the function as \( p \) (the number of people who pass on the money) increases.
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Identifying the range: Since \( m(p) = 20(2^p) \), when \( p = 0 \), \( m(0) = 20(2^0) = 20 \). As \( p \) increases, \( 2^p \) grows exponentially, which means \( m(p) \) will also grow significantly. Therefore, the range of \( m \) can be expressed as \( m \geq 20 \) since it reaches its minimum value at \( 20 \) when no one passes it on (i.e., when \( p = 0 \)) and increases without bound as \( p \) increases.
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Behavior as \( p \) increases:
- As \( p \) increases, \( m(p) \) does not decrease; it increases exponentially. Specifically, \( m(p) \) increases quickly at first (because \( 2^p \) increases quickly), and it continues to increase even more rapidly as \( p \) increases further. Therefore, the statement about \( m \) decreasing is incorrect.
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Domain: The domain of the function \( m(p) \) refers to the allowable values of \( p \). Since \( p \) represents the number of people who opt to pass on the money, it can take on non-negative integer values (0, 1, 2, 3, ...). Thus, the domain can be expressed as \( p \geq 0 \), not \( p \geq 20 \).
Based on this analysis, the statement that is true about the equation is:
The range (m-values) includes the values \( m \geq 20 \).