The equation given is \(m(p) = 20(2)^p\). Let's analyze it:
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As \(p\) (the number of people who opt to pass) increases, the term \(2^p\) increases exponentially. Therefore:
- As \(p\) increases, \(m\) increases quickly because you are doubling the amount each time a person passes the money on.
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Regarding the range (m-values):
- The minimum value of \(m\) occurs when \(p = 0\), which gives \(m(0) = 20(2)^0 = 20(1) = 20\). As \(p\) increases, \(m\) will continue to grow without bound, making the range \(m \geq 20\).
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Regarding the domain (p-values):
- The number of people passing on the money, \(p\), can start at 0 and can increase indefinitely (there is no upper limit). Therefore, the domain is \(p \geq 0\).
Based on this analysis, the correct statements are:
- As \(p\) increases, \(m\) increases quickly at first and then slowly.
- The range (m-values) includes the values \(m \geq 20\).
Ultimately, the true statement regarding the equation is:
- "As \(p\) increases, \(m\) increases quickly at first and then slowly." and "The range (m-values) includes the values \(m \geq 20\)."
The best response among your options would be:
The range (m-values) includes the values \(m \geq 20\).