Use the image to answer the question.

An illustration shows quadrant one of a coordinate plane where the x-axis and y-axis range from 0 to 6 in increments of 1. The y-axis is titled total cost in dollars and the x-axis is titled number of markers. A solid line, labeled A, is marked on the graph and passes through coordinates left parenthesis 0 comma 0 right parenthesis and left parenthesis 3 comma 6 right parenthesis. A dotted line, labeled B, passes through coordinates left parenthesis 0 comma 0 right parenthesis and left parenthesis 6 comma 3 right parenthesis.

Predict what the total cost would be for buying 10 of the type A markers.

(1 point)
Responses

$0.50
$0.50

$2.00
$2.00

$20.00
$20.00

$5.00
$5.00
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1 answer

To determine the total cost for buying 10 Type A markers, we first need to understand the relationship represented by line A in the graph.

According to the coordinates given (0, 0) and (3, 6) for line A, we can deduce the slope of the line. The coordinates suggest that for every 3 markers purchased (x = 3), it costs $6 (y = 6). This gives us the equation of the line:

  • The slope (cost per marker) can be calculated as follows: \[ \text{slope} = \frac{\text{change in y}}{\text{change in x}} = \frac{6 - 0}{3 - 0} = \frac{6}{3} = 2 \]

Thus, the cost per marker is $2.

Now, if we want to find the total cost for 10 markers, we can multiply the cost per marker by the number of markers: \[ \text{Total cost} = 2 \times 10 = 20 \]

So, the total cost would be $20.00.