Use the image to answer the question.

An illustration shows an arrow pointing both right and left. It is formed by triangles on the right and left connected by a rectangle in the middle. The length of the rectangle measures 16 inches, and the width measures 3 inches. The perpendicular height of the triangle on the right is shown by a horizontal dotted line from the right vertex to the base. The perpendicular height measures 8 inches. The length of the base of the triangle measures 10 inches.

A school hallway has a bidirectional arrow showing which way traffic can move. The dimensions of the sign are shown. What is the arrow’s area?

1 answer

To find the area of the bidirectional arrow, we first need to find the area of the two triangles and the rectangle separately, and then add them together.

Area of the right triangle:
Area = 0.5 x base x height
Area = 0.5 x 10 in x 8 in
Area = 40 square inches

Area of the left triangle:
Area = 0.5 x base x height
Area = 0.5 x 10 in x 8 in
Area = 40 square inches

Area of the rectangle:
Area = length x width
Area = 16 in x 3 in
Area = 48 square inches

Now, add the areas of the two triangles and the rectangle together:
Total area = 40 sq in + 40 sq in + 48 sq in
Total area = 128 square inches

Therefore, the area of the bidirectional arrow sign is 128 square inches.
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