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Question

An illustration shows an arrow pointing both right and left. It is formed by triangles on the right and left connected by a rectangle in the middle. The length of the rectangle measures 16 inches, and the width measures 3 inches. The perpendicular height of the triangle on the right is shown by a horizontal dotted line from the right vertex to the base. The perpendicular height measures 8 inches. The length of the base of the triangle measures 10 inches.

A school hallway has a bidirectional arrow showing which way traffic can move. The dimensions of the sign are shown. What is the arrow’s area?

(1 point)
Responses

208 in.2
208 in. squared

80 in.2
80 in. squared

48 in.2
48 in. squared

128 in.2
128 in. squared
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Answer 1

To find the area of the arrow, we need to find the areas of the two triangles on either side of the rectangle and then add them together.

Area of right triangle = 1/2 * base * height
Area of right triangle = 1/2 * 10 in * 8 in
Area of right triangle = 40 in²

Area of left triangle = 1/2 * base * height
Area of left triangle = 1/2 * 10 in * 8 in
Area of left triangle = 40 in²

Area of rectangle = length * width
Area of rectangle = 16 in * 3 in
Area of rectangle = 48 in²

Total area of arrow = 40 in² (right triangle) + 48 in² (rectangle) + 40 in² (left triangle)
Total area of arrow = 128 in²

Therefore, the arrow's area is 128 in².