To find the vertices of square A′B′C′D′ after reflecting square ABCD first across the x-axis and then across the y-axis, we can follow these steps:
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Reflect Across the x-axis: This changes the y-coordinates' sign.
- A(3, -4) → A'(3, 4)
- B(7, -4) → B'(7, 4)
- C(7, -8) → C'(7, 8)
- D(3, -8) → D'(3, 8)
After reflecting across the x-axis, the vertices are:
- A'(3, 4)
- B'(7, 4)
- C'(7, 8)
- D'(3, 8)
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Reflect Across the y-axis: This changes the x-coordinates' sign.
- A'(3, 4) → A''(-3, 4)
- B'(7, 4) → B''(-7, 4)
- C'(7, 8) → C''(-7, 8)
- D'(3, 8) → D''(-3, 8)
After reflecting across the y-axis, the final vertices for square A′B′C′D′ are:
- A′(-3, 4)
- B′(-7, 4)
- C′(-7, 8)
- D′(-3, 8)
So, the correct answer is: Square A′B′C′D′ has vertices A′(−3, 4), B′(−7, 4), C′(−7, 8), and D′(−3, 8).