Use the image to answer the question.

An illustration shows a rectangle that extends to a smaller rectangle at the bottom left. The length of the bottom rectangle is much lesser on the right. The dimensions are as follows: The larger rectangle shows the right side as 4, truncated bottom length as 3, and left side end to end as 5 including the extended rectangle. The smaller rectangle shows the bottom length as 2. There are 5 right angled symbols to show the perpendicular lines of the two rectangles.

What is the area of the composite figure in square units?(1 point)
square units

1 answer

To find the area of the composite figure, we will calculate the area of both rectangles and then sum them.

  1. Area of the larger rectangle:

    • The length of the larger rectangle is given as 4 units (right side).
    • The width of the larger rectangle is given as 5 units (left side end to end).
    • Area = Length × Width = 4 × 5 = 20 square units.
  2. Area of the smaller rectangle:

    • The length of the smaller rectangle (bottom length) is given as 2 units.
    • The width of the smaller rectangle can be determined from this figure. The height of the smaller rectangle is found by subtracting from the larger rectangle's height. Since the larger rectangle's height is not given directly, we observe that the height (width) must also equal the length of the larger rectangle's sides. Assuming that the left end is completely the rectangle's height (4 units).
    • Hence, the height of the smaller rectangle will be the total "height of larger" minus the bottom rectangle height.
    • Area = Length × Width = 2 × 3 = 6 square units.
  3. Total Area:

    • Total area = Area of larger rectangle + Area of smaller rectangle
    • Total area = 20 + 6 = 26 square units.

Thus, the area of the composite figure is \( \boxed{26} \) square units.

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