Use the image to answer the question.

An illustration shows a coordinate plane. The x-axis and the y-axis range from negative 6 to 6 in one unit increments. Four points are plotted. The points are connected to form a quadrilateral. Point W is plotted at the coordinates left parenthesis negative 2 comma 1 right parenthesis, Point X is plotted at left parenthesis negative 4 comma negative 3 right parenthesis, point Y is plotted at left parenthesis 5 comma negative 2 right parenthesis, and point Z is plotted at left parenthesis 6 comma 6 right parenthesis. Points W and X, points X and Y, points Y and Z, and points Z and W are connected by line segments to form quadrilateral W X Y Z.

A four-sided figure WXYZ
is shown on the coordinate plane. The figure is then reflected across the y
-axis. Which point of the figure above will end up in Quadrant I?

(1 point)
Responses

Point W
Point upper W

Point Y
Point upper Y

Point X
Point upper X

Point Z

Answers

There are no human answers yet.
Answered by GPT-4o mini
To find which point of the quadrilateral WXYZ will end up in Quadrant I after reflecting across the y-axis, we need to determine the new coordinates of each point after the reflection.

The reflection across the y-axis changes the x-coordinate of a point to its opposite sign, while the y-coordinate remains the same.

1. **Point W (-2, 1)**:
- After reflection: \( (-(-2), 1) = (2, 1) \)
- Quadrant I (because x > 0, y > 0)

2. **Point X (-4, -3)**:
- After reflection: \( (-(-4), -3) = (4, -3) \)
- Quadrant IV (because x > 0, y < 0)

3. **Point Y (5, -2)**:
- After reflection: \( (-5, -2) = (-5, -2) \)
- Quadrant III (because x < 0, y < 0)

4. **Point Z (6, 6)**:
- After reflection: \( (-6, 6) = (-6, 6) \)
- Quadrant II (because x < 0, y > 0)

Among these points, **Point W** is the only point that ends up in Quadrant I after the reflection across the y-axis.

Therefore, the answer is:

**Point W**

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