To find the vertices of square \( A'B'C'D' \) after reflecting square \( ABCD \) first across the x-axis and then across the y-axis, we can follow these steps:
-
Reflect across the x-axis:
- The rule for reflecting a point \( (x, y) \) across the x-axis is \( (x, -y) \).
- Applying this to each vertex:
- A \( (3, -4) \) becomes A' \( (3, 4) \)
- B \( (7, -4) \) becomes B' \( (7, 4) \)
- C \( (7, -8) \) becomes C' \( (7, 8) \)
- D \( (3, -8) \) becomes D' \( (3, 8) \)
-
Reflect across the y-axis:
- The rule for reflecting a point \( (x, y) \) across the y-axis is \( (-x, y) \).
- Applying this to the new vertices:
- A' \( (3, 4) \) becomes A'' \( (-3, 4) \)
- B' \( (7, 4) \) becomes B'' \( (-7, 4) \)
- C' \( (7, 8) \) becomes C'' \( (-7, 8) \)
- D' \( (3, 8) \) becomes D'' \( (-3, 8) \)
So, the vertices of square \( A'B'C'D' \) are:
- A'' \( (-3, 4) \)
- B'' \( (-7, 4) \)
- C'' \( (-7, 8) \)
- D'' \( (-3, 8) \)
The correct response is:
Square A′B′C′D′ has vertices A′(−3,4), B′(−7,4), C′(−7,8), and D′(−3,8).