Asked by Jayla
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An illustration shows a coordinate plane with four quadrants. The x-axis and y-axis both range from negative 7 to 7 in one unit increments. A wavy vertical line is graphed on the coordinate plane. he line passes through points plotted at left parenthesis negative 2 comma negative 3 right parenthesis, left parenthesis negative 1 comma negative 2 right parenthesis, left parenthesis 0 comma negative 1 right parenthesis, and left parenthesis 1 comma 6 right parenthesis.
Determine if the given graph is the graph of the function y=x−1
. Enter 1 for yes. Enter 2 for no.
(1 point)
Remaining Attempts : 3
An illustration shows a coordinate plane with four quadrants. The x-axis and y-axis both range from negative 7 to 7 in one unit increments. A wavy vertical line is graphed on the coordinate plane. he line passes through points plotted at left parenthesis negative 2 comma negative 3 right parenthesis, left parenthesis negative 1 comma negative 2 right parenthesis, left parenthesis 0 comma negative 1 right parenthesis, and left parenthesis 1 comma 6 right parenthesis.
Determine if the given graph is the graph of the function y=x−1
. Enter 1 for yes. Enter 2 for no.
(1 point)
Remaining Attempts : 3
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To determine if the given graph corresponds to the function \( y = x - 1 \), we can analyze the points given that lie on the wavy vertical line:
1. **For the point (-2, -3)**:
\[
y = -2 - 1 = -3 \quad \text{(matches)}
\]
2. **For the point (-1, -2)**:
\[
y = -1 - 1 = -2 \quad \text{(matches)}
\]
3. **For the point (0, -1)**:
\[
y = 0 - 1 = -1 \quad \text{(matches)}
\]
4. **For the point (1, 6)**:
\[
y = 1 - 1 = 0 \quad \text{(does not match)}
\]
Since the point \((1, 6)\) does not match the expected output of \( y = x - 1 \) at \( x = 1 \), the graph does not represent the function \( y = x - 1 \).
So the answer is: **2** (no).
1. **For the point (-2, -3)**:
\[
y = -2 - 1 = -3 \quad \text{(matches)}
\]
2. **For the point (-1, -2)**:
\[
y = -1 - 1 = -2 \quad \text{(matches)}
\]
3. **For the point (0, -1)**:
\[
y = 0 - 1 = -1 \quad \text{(matches)}
\]
4. **For the point (1, 6)**:
\[
y = 1 - 1 = 0 \quad \text{(does not match)}
\]
Since the point \((1, 6)\) does not match the expected output of \( y = x - 1 \) at \( x = 1 \), the graph does not represent the function \( y = x - 1 \).
So the answer is: **2** (no).
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