Use the image to answer the question.

An illustration shows a two-dimensional net of a triangular prism with all of its sides open and visible. The net appears as three vertical rectangles joined one on top of the other. All 4 sides of the middle rectangle are drawn with dashed lines. The width of the rectangles is 7 millimeters. The length of the middle rectangle is 8 millimeters. Two right triangles adjoin the middle rectangle on the left and the right, with the perpendicular sides measuring 6 millimeters and the hypotenuse measuring 10 millimeters.

Using the net of the prism shown, what is its surface area?

(1 point)
____ mm2

1 answer

To calculate the surface area of the triangular prism, we first need to find the areas of each of the individual shapes making up the net.

1. The area of the middle rectangle is length * width = 8 * 7 = 56 mm².
2. The combined area of the two right triangles is (1/2) * base * height, which is (1/2) * 6 * 8 = 24 mm² on each side. Since there are 2 triangles, the total area of the triangles is 2 * 24 = 48 mm².

Now, we can calculate the total surface area of the triangular prism by adding up the areas of all the shapes:
56 mm² (middle rectangle) + 48 mm² (two triangles) + 7 * 8 mm² (top and bottom rectangles) = 56 + 48 + 56 = 160 mm².

Therefore, the surface area of the triangular prism is 160 mm².