Use the image to answer the question.

An illustration shows a magnified, labeled figure of a two-part wing. The magnified two-part wing shows two similar pentagons, stacked in opposite directions upon each other, sharing a common base. The description of the top pentagon is as follows: The base is 1.4 meters, the bottom left, and right sides are smaller, and the top left and right sides are longer. A dashed line joining the top left and right vertices is labeled as 2.6 meters. The triangular region above this dashed line is shaded. The perpendicular distance from the top vertex to the dashed line is 0.3 meters, and from the dashed line to the base is 0.4 meters.

You are making a dragonfly kite. You want to cover the non-shaded area of the wings with shiny nylon. The dimensions of one pair of wings are shown. Decompose the figure into simple shapes. How many square meters of nylon will you need to cover the non-shaded area of one pair of wings?

(1 point)
Responses

1.19 square meters
1.19 square meters

2.38 square meters
2.38 square meters

1.99 square meters
1.99 square meters

3.98 square meters

1 answer

To simplify the figure, we can decompose it into a trapezoid (non-shaded top part) and two triangles (shaded parts).

The trapezoid's area can be calculated using the formula for the area of a trapezoid:
Area = (1/2) * (sum of parallel sides) * (height)
Area = (1/2) * (2.6 + 1.4) * 0.3
Area = (1/2) * 4 * 0.3
Area = 0.6 square meters

Each triangle's area can be calculated using the formula for the area of a triangle:
Area = (1/2) * base * height
Area = (1/2) * 1.4 * 0.4
Area = 0.28 square meters

Adding the trapezoid and the two triangles together:
0.6 + 0.28 + 0.28 = 1.16 square meters

Therefore, you will need 1.16 square meters of nylon to cover the non-shaded area of one pair of wings. The closest option is 1.19 square meters.
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