Use the image to answer the question.

An illustration shows a two-dimensional net of a triangular prism with all of its sides open and visible. The net appears as a rectangle, a square, and another rectangle joined horizontally next to each other. The width of the two rectangles and the side of the square measure 3 centimeters. The length of the left rectangle is 4 centimeters. The side of the middle square, drawn in a dashed line, is 3 centimeters. The length of the right rectangle is 5 centimeters. Two right triangles adjoin the middle square at the top and bottom, with each perpendicular side measuring 4 centimeters and each hypotenuse measuring 5 centimeters.

What is the surface area of the shown net for a triangular prism?

(1 point)

1 answer

To find the surface area of the triangular prism, we need to calculate the area of each face and then sum them up.

1. The area of the rectangle on the left side: Length x Width = 4 cm x 3 cm = 12 square cm
2. The area of the square in the middle: Side x Side = 3 cm x 3 cm = 9 square cm
3. The area of the rectangle on the right side: Length x Width = 5 cm x 3 cm = 15 square cm
4. The area of the two right triangles: (1/2) x Base x Height = (1/2) x 3 cm x 4 cm = 6 square cm for each triangle, so 6 cm x 2 = 12 square cm

Now, sum up the areas of all faces:
12 + 9 + 15 + 12 = 48 square cm

Therefore, the surface area of the shown net for the triangular prism is 48 square cm.
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