To find the surface area of the triangular prism net, we need to calculate the area of each individual shape and then add them all together.
1. Area of the left rectangle: 4 cm x 3 cm = 12 cm^2
2. Area of the right rectangle: 5 cm x 3 cm = 15 cm^2
3. Area of the square: 3 cm x 3 cm = 9 cm^2
4. Area of the two right triangles: (1/2) x 4 cm x 3 cm + (1/2) x 3 cm x 4 cm = 6 cm^2 + 6 cm^2 = 12 cm^2
Adding all these areas together:
12 cm^2 (left rectangle) + 15 cm^2 (right rectangle) + 9 cm^2 (square) + 12 cm^2 (two triangles) = 48 cm^2
Therefore, the surface area of the shown net for a triangular prism is 48 cm^2.
Use the image to answer the question.
An illustration shows a two-dimensional net of a triangular prism with all of its sides open and visible. The net appears as a rectangle, a square, and another rectangle joined horizontally next to each other. The width of the two rectangles and the side of the square measure 3 centimeters. The length of the left rectangle is 4 centimeters. The side of the middle square, drawn in a dashed line, is 3 centimeters. The length of the right rectangle is 5 centimeters. Two right triangles adjoin the middle square at the top and bottom, with each perpendicular side measuring 4 centimeters and each hypotenuse measuring 5 centimeters.
What is the surface area of the shown net for a triangular prism?
(1 point)
____cm2
1 answer
1 answer