Use the image to answer the question.

An illustration shows a triangular prism placed sideways with one of its rectangular faces as the base. Dimensions are labeled. The length and width of the rectangular base are 17 centimeters and 13 centimeters respectively. The face visible in front appears as a triangle. The base width of the triangle is 13 centimeters. The perpendicular leg of the triangle is 7.48 centimeters and the slanting leg (hypotenuse) is 15 centimeters. The edges that are not visible are represented by dashed lines.

Apply the technique of using nets to find the surface area of this triangular prism. Your answer should have two decimal places.

(1 point)
Responses

700.40 cm2
700.40 cm squared

603.16 cm2
603.16 cm squared

573.24 cm2
573.24 cm squared

97.24 cm2

1 answer

To find the surface area of the triangular prism, we need to find the area of each face and then add them up.

Area of the rectangular faces:
2 * (length * width) = 2 * (17 * 13) = 442 cm²

Area of the triangular faces:
Base * Height / 2 = 13 * 7.48 / 2 = 48.74 cm² (for each triangle, there are two, one on each end).

Total surface area:
442 (rectangular faces) + 2 * 48.74 (two triangular faces) = 539.48 cm²

Rounded to two decimal places, the surface area of the triangular prism is: 539.48 cm²

Therefore, the closest answer is 603.16 cm².