Use the image to answer the question.
An illustration shows a two-dimensional net of a triangular prism with all of its sides open and visible. The net appears as three horizontal rectangles joined next to each other. All 4 sides of the middle rectangle are drawn with dashed lines. The width of the 3 rectangles is 1 centimeter. The length of the outer rectangles is 2.5 centimeters. The length of the middle rectangle is 3 centimeters. Two right triangles adjoin the middle rectangle on the top and bottom along the 3 centimeter side, with their perpendicular height measuring 2 centimeters. A right angle is shown where the perpendicular height intersects with the triangle base.
What is the surface area of the triangular prism whose net is shown?
(1 point)
Responses
8 cm2
8 cm squared
6 cm2
6 cm squared
2.48 cm2
2.48 cm squared
14 cm2
14 cm squared
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1 answer
The lateral area of the rectangular sides is found by multiplying the sum of the lengths of the rectangles by the width:
2.5 cm + 3 cm + 2.5 cm = 8 cm
8 cm * 1 cm = 8 cm²
The area of the two triangular bases can be found by multiplying the base by the height, and dividing by 2 (for each triangle):
3 cm * 2 cm / 2 = 3 cm * 1 cm = 3 cm² for each triangle
2 triangles * 3 cm² = 6 cm²
Therefore, the total surface area of the triangular prism is 8 cm² (lateral area) + 6 cm² (two triangular bases) = 14 cm².
The correct answer is:
14 cm²