Use the image to answer the question.
An illustration shows a two-dimensional net of a triangular prism with all of its sides open and visible. The net appears as three horizontal parallelograms joined next to each other. All 4 sides of the middle parallelogram are drawn with dashed lines. The width of the parallelograms is 4 centimeters. The length of the middle parallelogram is 12 centimeters. Two right triangles adjoin the middle parallelogram on the top and bottom 12 centimeter sides, with their hypotenuse sides measuring 15 centimeters and the perpendicular sides measuring 9 centimeters. Right angles are shown at the intersection of the perpendicular sides and the base sides of the triangles.
What is the surface area of the triangular prism whose net is shown?
(1 point)
Responses
198 cm2
198 cm squared
108 cm2
108 cm squared
252 cm2
252 cm squared
216 cm2
216 cm squared
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3 answers
First, the surface area of the two parallelograms can be calculated as 2 x (4 cm x 12 cm) = 96 cm².
Next, the surface area of the two triangles can be calculated as 2 x (1/2 x 9 cm x 12 cm) = 108 cm².
Adding all the areas together:
96 cm² (parallelograms) + 108 cm² (triangles) = 204 cm².
Therefore, the correct answer is not listed in the provided options.