To find the surface area of the net diagram of the right circular cylinder, we need to find the lateral surface area and the surface area of the two circular bases.
The lateral surface area of a cylinder is calculated using the formula: 2πrh, where r is the radius and h is the height.
Given that the radius is 10 inches and the height is 9 inches, the lateral surface area is:
2(3.14)(10)(9) = 564.72 square inches
The surface area of each circular base is πr². Since there are two circular bases, the total surface area of the bases is:
2(3.14)(10)² = 628 square inches
Adding the lateral surface area and the surface area of the bases gives us the total surface area of the net diagram of the right circular cylinder:
564.72 + 628 = 1192.72 square inches
Therefore, the surface area of the net diagram of the right circular cylinder is 1192.72 square inches.
Use the image to answer the question.
An illustration shows a horizontal rectangle of height 9 inches with a circle of radius 10 inches attached to its top left and a circle of radius 10 inches attached to its bottom right.
Find the surface area of the net diagram of the right circular cylinder. Use 3.14 for π .
(1 point)
____ inches2
9 answers
Use the image to answer the question.
An illustration shows a horizontal rectangle of height 9 inches with a circle of radius 10 inches attached to its top left and a circle of radius 10 inches attached to its bottom right.
Find the surface area of the net diagram of the right circular cylinder. Use 3.14 for π .
(1 point)
___ inches2
An illustration shows a horizontal rectangle of height 9 inches with a circle of radius 10 inches attached to its top left and a circle of radius 10 inches attached to its bottom right.
Find the surface area of the net diagram of the right circular cylinder. Use 3.14 for π .
(1 point)
___ inches2
To find the surface area of the net diagram of the right circular cylinder, we need to find the lateral surface area and the surface area of the two circular bases.
Given that the height of the rectangle is 9 inches, we know that this will be the height of the cylinder as well.
The lateral surface area of a cylinder is given by the formula 2πrh, where r is the radius and h is the height. Since the radius is 10 inches and the height is 9 inches, the lateral surface area is:
2 * 3.14 * 10 * 9 = 564.6 square inches
The surface area of each circular base is πr². Since there are two circular bases, the total surface area of the bases is:
2 * 3.14 * 10² = 628 square inches
Adding the lateral surface area and the surface area of the bases, we get the total surface area of the net diagram of the right circular cylinder:
564.6 + 628 = 1192.6 square inches
Therefore, the surface area of the net diagram of the right circular cylinder is 1192.6 square inches.
Given that the height of the rectangle is 9 inches, we know that this will be the height of the cylinder as well.
The lateral surface area of a cylinder is given by the formula 2πrh, where r is the radius and h is the height. Since the radius is 10 inches and the height is 9 inches, the lateral surface area is:
2 * 3.14 * 10 * 9 = 564.6 square inches
The surface area of each circular base is πr². Since there are two circular bases, the total surface area of the bases is:
2 * 3.14 * 10² = 628 square inches
Adding the lateral surface area and the surface area of the bases, we get the total surface area of the net diagram of the right circular cylinder:
564.6 + 628 = 1192.6 square inches
Therefore, the surface area of the net diagram of the right circular cylinder is 1192.6 square inches.
Can you just give the correct answer please?
Sure! The correct answer is:
1192.6 square inches
1192.6 square inches
Its still not correct like whats wrong with you?
I apologize for the previous incorrect responses. Let's determine the correct surface area of the net diagram of the right circular cylinder.
The net diagram consists of the rectangle and two circles.
The area of the rectangle is given by:
Area_rectangle = length * width = 2 * 9 = 18 square inches
The area of each circle is:
Area_circle = π * r² = 3.14 * 10² = 3.14 * 100 = 314 square inches
Since there are two circles, the total area of the circles is:
2 * 314 = 628 square inches
The lateral surface area of the cylinder can be calculated as:
Lateral_surface_area = height * perimeter of base = 9 * 2 * π * r = 9 * 2 * 3.14 * 10 = 565.2 square inches
Adding the area of the rectangle, the areas of the two circles, and the lateral surface area of the cylinder, we get:
18 + 628 + 565.2 = 1211.2 square inches
Therefore, the correct surface area of the net diagram of the right circular cylinder is 1211.2 square inches.
The net diagram consists of the rectangle and two circles.
The area of the rectangle is given by:
Area_rectangle = length * width = 2 * 9 = 18 square inches
The area of each circle is:
Area_circle = π * r² = 3.14 * 10² = 3.14 * 100 = 314 square inches
Since there are two circles, the total area of the circles is:
2 * 314 = 628 square inches
The lateral surface area of the cylinder can be calculated as:
Lateral_surface_area = height * perimeter of base = 9 * 2 * π * r = 9 * 2 * 3.14 * 10 = 565.2 square inches
Adding the area of the rectangle, the areas of the two circles, and the lateral surface area of the cylinder, we get:
18 + 628 + 565.2 = 1211.2 square inches
Therefore, the correct surface area of the net diagram of the right circular cylinder is 1211.2 square inches.
1211.2 is not the answer bro
I apologize for the oversight. Let's reevaluate the calculation.
The net diagram of the right circular cylinder consists of one rectangle and two circles.
The area of the rectangle is:
Area_rectangle = length * width = 2 * 9 = 18 square inches
The area of each circle is:
Area_circle = π * r² = 3.14 * 10² = 3.14 * 100 = 314 square inches
Since there are two circles, the total area of the circles is:
2 * 314 = 628 square inches
The lateral surface area of the cylinder can be calculated as:
Lateral_surface_area = height * perimeter of base = 9 * 2 * π * r = 9 * 2 * 3.14 * 10 = 565.2 square inches
Adding the area of the rectangle, the areas of the two circles, and the lateral surface area of the cylinder, we get:
18 + 628 + 565.2 = 1211.2 square inches
Therefore, the correct surface area of the net diagram of the right circular cylinder is 1211.2 square inches.
The net diagram of the right circular cylinder consists of one rectangle and two circles.
The area of the rectangle is:
Area_rectangle = length * width = 2 * 9 = 18 square inches
The area of each circle is:
Area_circle = π * r² = 3.14 * 10² = 3.14 * 100 = 314 square inches
Since there are two circles, the total area of the circles is:
2 * 314 = 628 square inches
The lateral surface area of the cylinder can be calculated as:
Lateral_surface_area = height * perimeter of base = 9 * 2 * π * r = 9 * 2 * 3.14 * 10 = 565.2 square inches
Adding the area of the rectangle, the areas of the two circles, and the lateral surface area of the cylinder, we get:
18 + 628 + 565.2 = 1211.2 square inches
Therefore, the correct surface area of the net diagram of the right circular cylinder is 1211.2 square inches.