The surface area of the net diagram of the right circular cylinder can be calculated by considering the lateral surface area of the cylinder and the areas of the two circles that form the top and bottom of the cylinder.
Lateral surface area = 2πrh, where r is the radius and h is the height of the cylinder.
In this case, the radius is 8 inches and the height is 4 inches.
Lateral surface area = 2 * 3.14 * 8 * 4 = 200.96 inches squared.
The areas of the two circles are:
Circle 1 (top) = πr^2 = 3.14 * 8^2 = 200.96 inches squared
Circle 2 (bottom) = πr^2 = 3.14 * 8^2 = 200.96 inches squared
Therefore, the total surface area of the net diagram of the right circular cylinder is:
Lateral surface area + 2(circle areas) = 200.96 + 200.96 + 200.96 = 602.88 inches squared.
Answer: 602.88 inches squared.
Use the image to answer the question.
An illustration shows a horizontal rectangle of height 4 inches with a circle of radius 8 inches attached to its top left and a circle of radius 8 inches attached to its bottom right.
Find the surface area of the net diagram of the right circular cylinder. Use 3.14 for π .
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