To find the surface area of the net diagram of the right circular cylinder, we need to find the total surface area of the rectangle and the surface area of the two circles.
The rectangle has a height of 4 inches and a width of 8 inches, so its surface area is 4 inches x 8 inches = 32 square inches.
Each circle has a radius of 8 inches, so the surface area of one circle is πr^2 = 3.14 x 8^2 = 3.14 x 64 = 200.96 square inches. Since there are two circles, the total surface area of the circles is 2 x 200.96 = 401.92 square inches.
Therefore, the total surface area of the net diagram of the right circular cylinder is 32 + 401.92 = 433.92 square inches.
Use the image to answer the question.
An illustration shows a horizontal rectangle of height 4 inches with a circle of radius 8 inches attached to its top left and a circle of radius 8 inches attached to its bottom right.
Find the surface area of the net diagram of the right circular cylinder. Use 3.14 for π .
(1 point)
inches2
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To find the surface area of the net diagram of the right circular cylinder, we need to find the total surface area of the rectangle and the surface area of the two circles.
The rectangle has a height of 4 inches and a width of 8 inches, so its surface area is 4 inches x 8 inches = 32 square inches.
Each circle has a radius of 8 inches, so the surface area of one circle is πr^2 = 3.14 x 8^2 = 3.14 x 64 = 200.96 square inches. Since there are two circles, the total surface area of the circles is 2 x 200.96 = 401.92 square inches.
Therefore, the total surface area of the net diagram of the right circular cylinder is 32 + 401.92 = 433.92 square inches.
The rectangle has a height of 4 inches and a width of 8 inches, so its surface area is 4 inches x 8 inches = 32 square inches.
Each circle has a radius of 8 inches, so the surface area of one circle is πr^2 = 3.14 x 8^2 = 3.14 x 64 = 200.96 square inches. Since there are two circles, the total surface area of the circles is 2 x 200.96 = 401.92 square inches.
Therefore, the total surface area of the net diagram of the right circular cylinder is 32 + 401.92 = 433.92 square inches.
The correct calculation for the total surface area of the net diagram of the right circular cylinder is as follows:
Rectangle surface area = 8 inches (width) x 4 inches (height) = 32 square inches
Surface area of one circle = πr^2 = 3.14 x 8^2 = 3.14 x 64 = 200.96 square inches
Total surface area of the two circles = 2 x 200.96 = 401.92 square inches
Total surface area of the net diagram = Rectangle surface area + Total surface area of the two circles
= 32 square inches + 401.92 square inches
= 433.92 square inches
Therefore, the surface area of the net diagram of the right circular cylinder is 433.92 square inches.
Rectangle surface area = 8 inches (width) x 4 inches (height) = 32 square inches
Surface area of one circle = πr^2 = 3.14 x 8^2 = 3.14 x 64 = 200.96 square inches
Total surface area of the two circles = 2 x 200.96 = 401.92 square inches
Total surface area of the net diagram = Rectangle surface area + Total surface area of the two circles
= 32 square inches + 401.92 square inches
= 433.92 square inches
Therefore, the surface area of the net diagram of the right circular cylinder is 433.92 square inches.
Thats not correct
5 answers