To translate a figure, you need to add or subtract the same value from the x and y coordinates of each point. In this case, the figure is being translated 6 units up and 4 units to the left.
To find the coordinates of point S', we can subtract 4 from the x-coordinate and add 6 to the y-coordinate of point S.
The original coordinates of point S are (2, 2).
Subtracting 4 from the x-coordinate, we get: 2 - 4 = -2.
Adding 6 to the y-coordinate, we get: 2 + 6 = 8.
Therefore, the coordinates of point S' are (-2, 8).
Use the image to answer the question.
An illustration shows a coordinate plane. Both x- and y-axes range from negative 10 to 10 in one unit increments. A quadrilateral with vertices P Q R S is drawn on it. Vertex P is at coordinates left parenthesis 4 comma 6 right parenthesis, vertex Q is at coordinates left parenthesis 7 comma 2 right parenthesis, vertex R is at coordinates left parenthesis 5 comma negative 2 right parenthesis, and vertex S is at coordinates left parenthesis 2 comma 2 right parenthesis.
If figure PQRS is translated 6 units up and 4 units to the left, what are the coordinates of point S′?
(1 point)
1 answer