To determine who has greater kinetic energy between the wildlife keeper and the rabbit, we can use the kinetic energy formula:
\[ KE = \frac{1}{2} mv^2 \]
where \( KE \) is kinetic energy, \( m \) is mass, and \( v \) is velocity.
For the wildlife keeper:
- Mass (\( m \)) = 60 kg
- Velocity (\( v \)) = 5 m/s
Calculating the kinetic energy of the wildlife keeper:
\[ KE_{keeper} = \frac{1}{2} \times 60 , \text{kg} \times (5 , \text{m/s})^2 = \frac{1}{2} \times 60 \times 25 = 750 , \text{Joules} \]
For the rabbit:
- Mass (\( m \)) = 4 kg
- Velocity (\( v \)) = 5 m/s
Calculating the kinetic energy of the rabbit:
\[ KE_{rabbit} = \frac{1}{2} \times 4 , \text{kg} \times (5 , \text{m/s})^2 = \frac{1}{2} \times 4 \times 25 = 50 , \text{Joules} \]
Comparing the two kinetic energies:
- Kinetic energy of the wildlife keeper = 750 Joules
- Kinetic energy of the rabbit = 50 Joules
Thus, the wildlife keeper has the greater kinetic energy because they have a greater mass.
The correct response is:
The wildlife keeper because they have a greater mass.