To determine who has the greater kinetic energy, we can use the formula for kinetic energy (KE):
\[ KE = \frac{1}{2} m v^2 \]
Where:
- \( m \) is the mass,
- \( v \) is the speed.
For the wildlife keeper:
- Mass (\( m \)) = 60 kg
- Speed (\( v \)) = 5 m/s
Calculating kinetic energy for the wildlife keeper: \[ KE_{\text{keeper}} = \frac{1}{2} \times 60 , \text{kg} \times (5 , \text{m/s})^2 = \frac{1}{2} \times 60 \times 25 = 750 , \text{J} \]
For the rabbit:
- Mass (\( m \)) = 4 kg
- Speed (\( v \)) = 5 m/s
Calculating kinetic energy for the rabbit: \[ KE_{\text{rabbit}} = \frac{1}{2} \times 4 , \text{kg} \times (5 , \text{m/s})^2 = \frac{1}{2} \times 4 \times 25 = 50 , \text{J} \]
Comparing the two kinetic energies:
- Kinetic energy of the wildlife keeper = 750 J
- Kinetic energy of the rabbit = 50 J
Since 750 J > 50 J, the wildlife keeper has the greater kinetic energy.
Therefore, the correct response is: The wildlife keeper because they have a greater mass.