To compare the kinetic energy of the wildlife keeper and the rabbit, we can use the formula for kinetic energy:
\[ KE = \frac{1}{2} m v^2 \]
Where \( m \) is the mass and \( v \) is the speed.
Given:
- Wildlife keeper mass = 60 kg
- Rabbit mass = 4 kg
- Speed of both = 5 m/s
Calculating the kinetic energy for both:
-
Wildlife Keeper's Kinetic Energy: \[ KE_{keeper} = \frac{1}{2} \times 60 , kg \times (5 , m/s)^2 \] \[ KE_{keeper} = \frac{1}{2} \times 60 \times 25 \] \[ KE_{keeper} = \frac{1}{2} \times 1500 \] \[ KE_{keeper} = 750 , J \]
-
Rabbit's Kinetic Energy: \[ KE_{rabbit} = \frac{1}{2} \times 4 , kg \times (5 , m/s)^2 \] \[ KE_{rabbit} = \frac{1}{2} \times 4 \times 25 \] \[ KE_{rabbit} = \frac{1}{2} \times 100 \] \[ KE_{rabbit} = 50 , J \]
Comparing the two:
- Kinetic Energy of the wildlife keeper = 750 J
- Kinetic Energy of the rabbit = 50 J
Conclusion: The wildlife keeper has the greater kinetic energy because they have a greater mass.
The correct response is:
The wildlife keeper because they have a greater mass.