SA=(1/2 * 17 * 14.72) + (1/2 * 3 * 11 * 10.99)
SA= (8.5 * 14.72) + (16.5 * 10.99)
SA= 125.72 + 181.635
SA= 307.355
Therefore, the equation for the surface area of the triangular pyramid net shown in the image is SA = 307.355 square millimeters.
Use the image to answer the question.
An illustration of a triangular pyramid net shows an inverted equilateral triangle as the base, with sides measuring 17 millimeters. Three identical isosceles triangles extend from each side of the base. A dashed line bisects the central inverted triangle and is labeled as h equals 14.72 millimeters. The outer edges of the three isosceles triangles joined to the 17 millimeter base are all labeled as 11 millimeters. A dashed line bisects the outer triangle on the left and is labeled as h equals 10.99 millimeters.
Write the equation for the surface area of the triangular pyramid net shown in the image. Remember, SA=(12base⋅height)+(12perimeter⋅slant height)
(2 points)
SA=(12⋅⋅)+(12⋅⋅)
1 answer