Use the image to answer the question.

An illustration of a scatterplot graph shows x-axis ranging from 0 to 15 in increments of 1 and y-axis ranging from 0 to 75 in increments of 5. Multiple points are plotted and a line points upward to the right with an arrowhead on the top. The line passes approximately through left parenthesis 0 comma 25 right parenthesis, left parenthesis 1 comma 30 right parenthesis, left parenthesis 2 comma 35 right parenthesis, left parenthesis 7 comma 60 right parenthesis, and left parenthesis 10 comma 75 right parenthesis. 5 points are plotted to the line.

Write an equation in slope-intercept form of the trend line.
(1 point)

1 answer

To find the equation of the trend line in slope-intercept form, we first need to determine the slope of the line. We can do this by calculating the change in y divided by the change in x between two points on the line. Let's choose the points (0, 25) and (10, 75) to calculate the slope.

Slope = (75 - 25) / (10 - 0) = 50 / 10 = 5

Now that we have the slope, we can use the point-slope form of a linear equation to find the equation of the line. Let's choose the point (0, 25) to do this.

y - 25 = 5(x - 0)
y - 25 = 5x
y = 5x + 25

Therefore, the equation of the trend line in slope-intercept form is y = 5x + 25.