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Question

An illustration of a coordinate plane with four quadrants shows the x-axis ranging from negative 9 to 9 and the y-axis ranging from negative 11 to 11 in increments of 1. A solid downward line with arrows at both ends is plotted on the graph. The line passes through the plotted points left parenthesis 0 comma 1 right parenthesis and left parenthesis 1 comma negative 4 right parenthesis.

Write the equation of the line in slope-intercept form.

(1 point)
Responses

y=−5x−1
y equals negative 5 x minus 1

y=−5x+1
y equals negative 5 x plus 1

y=5x+1
y equals 5 x plus 1

−5x−y=−1
negative 5 x minus y equals negative 1
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Answer 1

To find the equation of the line in slope-intercept form (y = mx + b), we need to determine the slope (m) and the y-intercept (b).

1. Calculate the slope (m): Use the points (0, 1) and (1, -4). \[ m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-4 - 1}{1 - 0} = \frac{-5}{1} = -5 \]

2. Use the slope and a point to find b: We can use the point (0, 1) to find the y-intercept (b): \[ y = mx + b \implies 1 = -5(0) + b \implies b = 1 \]

3. Write the equation: Substitute the values of m and b into the slope-intercept form: \[ y = -5x + 1 \]

Thus, the equation of the line in slope-intercept form is: \[ y = -5x + 1 \]

The correct response is: y = −5x + 1