The total number of segments on the wheel is 6, and there are 2 shaded segments (S and E). Therefore, the number of unshaded segments is 6 - 2 = 4.
The probability of landing on an unshaded section is the number of unshaded segments divided by the total number of segments, which is 4/6 = 2/3 or \(\frac{2}{3}\).
So, the correct response is: Start Fraction 2 over 3 End Fraction
Use the image to answer the question.
A wheel is divided into 6 segments from the center toward circumference and labeled from the left as S, T, H, O, N, and E. The arrow of a needle points to O on the right and the circular end points to S on the left.
A spinner labeled with the letters of the word HONEST is to be spun once. Describe the probability of landing on an unshaded section in the sample space.
(1 point)
Responses
13
Start Fraction 1 over 3 End Fraction
16
Start Fraction 1 over 6 End Fraction
12
Start Fraction 1 over 2 End Fraction
3
3 answers
no
Choose
Use the image to answer the question.
A wheel is divided into 6 segments from the center toward circumference and labeled from the left as S, T, H, O, N, and E. The arrow of a needle points to O on the right and the circular end points to S on the left.
A spinner labeled with the letters of the word HONEST is to be spun once. Describe the probability of landing on an unshaded section in the sample space.
(1 point)
Responses
CHOOSE
13
Start Fraction 1 over 3 End Fraction
16
Start Fraction 1 over 6 End Fraction
12
Start Fraction 1 over 2 End Fraction
3
Choose
Use the image to answer the question.
A wheel is divided into 6 segments from the center toward circumference and labeled from the left as S, T, H, O, N, and E. The arrow of a needle points to O on the right and the circular end points to S on the left.
A spinner labeled with the letters of the word HONEST is to be spun once. Describe the probability of landing on an unshaded section in the sample space.
(1 point)
Responses
CHOOSE
13
Start Fraction 1 over 3 End Fraction
16
Start Fraction 1 over 6 End Fraction
12
Start Fraction 1 over 2 End Fraction
3
Apologies for the previous error.
Given that the spinner is labeled with the word HONEST and the needle is pointing to O on the right and the circular end points to S on the left, we can determine the unshaded section as H, N, and T.
There are 3 unshaded sections out of a total of 6 sections on the spinner.
Therefore, the probability of landing on an unshaded section is 3 out of 6, which can be simplified to 1/2.
So, the correct response is: Start Fraction 1 over 2 End Fraction.
Given that the spinner is labeled with the word HONEST and the needle is pointing to O on the right and the circular end points to S on the left, we can determine the unshaded section as H, N, and T.
There are 3 unshaded sections out of a total of 6 sections on the spinner.
Therefore, the probability of landing on an unshaded section is 3 out of 6, which can be simplified to 1/2.
So, the correct response is: Start Fraction 1 over 2 End Fraction.
2 answers