To determine which point is a solution to the inequalities \( y > 3x + 1 \) and \( y \leq 2x + 5 \), we first need to identify the areas defined by these inequalities.
-
For the inequality \( y > 3x + 1 \):
- The line \( y = 3x + 1 \) serves as a boundary. The area above this line (but not including the line itself) represents the solutions to this inequality.
-
For the inequality \( y \leq 2x + 5 \):
- The line \( y = 2x + 5 \) serves as another boundary. The area below this line (including the line itself) represents the solutions to this inequality.
Next, we would normally graph these lines to determine the regions of interest, but since we don't have the image, let's discuss how you would proceed with testing the given points against these inequalities.
To identify which point (x, y) satisfies both inequalities:
- Substitute the x-value of the point into both inequalities:
- For \( y > 3x + 1 \), check if the y-value is greater than \( 3x + 1 \).
- For \( y \leq 2x + 5 \), check if the y-value is less than or equal to \( 2x + 5 \).
After evaluating each point, the solution(s) satisfying both inequalities will be your answer(s).
If you can provide the coordinates of the three points or further describe their locations on the graph, I can help analyze which one (if any) meets both conditions.