To find the centroid of triangle \( ABC \) with vertices \( A(2, 2) \), \( B(8, 2) \), and \( C(4, 7) \), we can use the formula for the centroid \( G \) of a triangle given its vertices \( (x_1, y_1) \), \( (x_2, y_2) \), and \( (x_3, y_3) \):
\[ G\left( \frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3} \right) \]
Substituting the coordinates of the vertices:
- \( (x_1, y_1) = (2, 2) \)
- \( (x_2, y_2) = (8, 2) \)
- \( (x_3, y_3) = (4, 7) \)
Calculating the \( x \)-coordinate of the centroid:
\[ x_G = \frac{2 + 8 + 4}{3} = \frac{14}{3} \]
Calculating the \( y \)-coordinate of the centroid:
\[ y_G = \frac{2 + 2 + 7}{3} = \frac{11}{3} \]
Thus, the coordinates of the centroid \( G \) of triangle \( ABC \) are:
\[ \text{centroid} = \left( \frac{14}{3}, \frac{11}{3} \right) \]
In conclusion, the centroid is
\[ \boxed{\left( \frac{14}{3}, \frac{11}{3} \right)} \]