To prove that the diagonals of rectangle ABCD are congruent, we utilize the properties of triangles and the congruence of their parts. Given the previous statements:
- \(AD \cong BC\)
- \(AB \cong AB\) (reflexive property)
- \(\angle DAB \cong \angle CBA\) (corresponding angles in a rectangle)
The next logical step is to compare triangles that incorporate the intersection point \(O\) of the diagonals \(AC\) and \(BD\).
The best option that logically follows the previous statements is:
△DAB ≅ △CBA
This states that triangle ADB is congruent to triangle CBA, using Side-Angle-Side (SAS) congruence because we have already established two pairs of corresponding sides and the included angle.
Thus, the correct response is:
△DAB≅△CBA (triangle ADB congruent to triangle CBA).