To determine which statement is true regarding the graph of the parabola, we need to consider a few characteristics of parabolas:
- The c-value in the standard form of a quadratic equation \( y = ax^2 + bx + c \) represents the y-intercept of the graph, which is the point where the graph intersects the y-axis (when \( x = 0 \)).
- The a-value determines the direction (upwards if \( a > 0 \) and downwards if \( a < 0 \)) and the width of the parabola.
- The vertex of the parabola is its highest or lowest point, depending on the direction it opens.
From the information provided:
- If the graph shows the parabola intersects the y-axis at (0, -10), then the c-value is indeed -10.
- If the parabola opens downwards, the a-value is negative.
- If the vertex is shown to be at (3, -10), that would contradict the typical calculations, as the vertex’s x-value being greater than the y-intercept at (0, -10) suggests a different location.
Based on these observations:
- If the parabola intersects the y-axis at (0, -10), then the c-value in standard form is -10 is true.
- If the parabola opens downwards (typical of a negative a-value), then the a-value is negative is also true.
- If the vertex is at (3, -10), this would likely be incorrect considering the location of the y-intercept unless it is defined as such by the specific graph.
To answer your query without visual confirmation, the most certain statement would likely be:
- The c-value of the equation in standard form is −10.