The depth of swimmer's dive can be determined by finding the minimum point on the parabola. This point represents the lowest vertical position of the swimmer during the dive. The minimum point of a parabola in the form y = ax^2 + bx + c is given by the vertex formula x = -b/2a.
Since the x-coordinate of the minimum point is 4 in this case, the swimmer's dive was 4 units deep.
Use the image to answer the question.
A parabola is graphed on a coordinate plane. The x-axis ranges from 0 to 8 in increments of 1. The y-axis ranges from negative 5 to 5 in increments of 1.
A swimmer’s dive is modeled in the graph, in which x is the distance from the pool’s front wall and y is the swimmer’s vertical position. How deep was the swimmer’s dive?
(1 point)
The swimmer’s dive was
units deep.
1 answer
1 answer