Use the image to answer the question.

A number line is shown ranging from negative 10 to 10 with numbers listed in unit increments. A closed point is plotted on the number line between 1 and 2. A rightward arrow is marked on the number line that originates at the closed point and goes beyond 10.

Preston solved an inequality and graphed the solution on the number line. Which of the following inequalities did he solve?

(1 point)
Responses

0.9x+2.8≤5.95
0.9 x plus 2.8 less than or equal to 5.95

5.6x−18.9≤0.7
5.6 x minus 18.9 less than or equal to 0.7

3.4x−1.2≥4.75
3.4 x minus 1.2 greater than or equal to 4.75

2.1x+5.6≥8.75
2.1 x plus 5.6 greater than or equal to 8.75

1 answer

To determine which inequality Preston solved based on the number line described, we can analyze the closed point plotted between 1 and 2, along with the rightward arrow extending beyond 10. The closed point indicates that the value is included in the solution set, and the rightward arrow suggests that the solution includes all values greater than or equal to that point.

Since the point is between 1 and 2, we can infer that it is likely around 1.5 or so. Because the rightward arrow extends beyond 10, it suggests that the solution encompasses all values from this point onwards.

Next, we'll check each of the provided inequalities.

  1. 0.9x + 2.8 ≤ 5.95

    • Solving for x: \( 0.9x \leq 5.95 - 2.8 \) \( 0.9x \leq 3.15 \) \( x \leq \frac{3.15}{0.9} \approx 3.5 \)
    • This does not match since it is leftward and does not go beyond 10.
  2. 5.6x - 18.9 ≤ 0.7

    • Solving for x: \( 5.6x \leq 0.7 + 18.9 \) \( 5.6x \leq 19.6 \) \( x \leq \frac{19.6}{5.6} \approx 3.5 \)
    • This also does not match since it is leftward.
  3. 3.4x - 1.2 ≥ 4.75

    • Solving for x: \( 3.4x \geq 4.75 + 1.2 \) \( 3.4x \geq 5.95 \) \( x \geq \frac{5.95}{3.4} \approx 1.75 \)
    • This inequality has a rightward solution from around 1.75, which matches with a rightward arrow that goes beyond 10.
  4. 2.1x + 5.6 ≥ 8.75

    • Solving for x: \( 2.1x \geq 8.75 - 5.6 \) \( 2.1x \geq 3.15 \) \( x \geq \frac{3.15}{2.1} \approx 1.5 \)
    • This also has a rightward solution but is less than the previous one.

Given this analysis, the most appropriate inequality that Preston solved, which correlates with the closed point on the number line as well as the rightward arrow beyond 10, is:

3.4x - 1.2 ≥ 4.75

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