To find the distance between landmark A and landmark E, we can use the coordinates given in the image.
Landmark A is located at 4 units across and 3 units down. Landmark E is located at 12 units across and 3 units down.
Since they have the same y-coordinate (3 units down), the distance between them is simply the difference in their x-coordinates.
12 - 4 = 8 units
Therefore, the length between landmark A and landmark E is 8 units.
Use the image to answer the question.
A map shows a grid 17 units across and 12 units high, superimposed over shapes that represent streets and buildings. A key lists buildings located in Washington D.C. that correspond to points on the grid. Point A represents the White House. It is located at 4 units across from the left, and 3 units down from the top. Point B represents the Washington Monument, located at 5 units across and 9 units down. Point C represents the Natural History Museum, and is located at approximately 8 units across and 8 units down. Point D represents the Smithsonian, and is located at 10 units across and 10 units down. Point E represents the National Portrait Gallery, and is located at 12 units across and 3 units down. Point F represents the National Gallery of Art, and is located at 14 units across and 8 units down. A scale shows 200 feet and 200 meters.
Find the length between landmark A and landmark E.
(1 point)
units
9 answers
Use the image to answer the question.
A map shows a grid 17 units across and 12 units high, superimposed over shapes that represent streets and buildings. A key lists buildings located in Washington D.C. that correspond to points on the grid. Point A represents the White House. It is located at 4 units across from the left, and 3 units down from the top. Point B represents the Washington Monument, located at 5 units across and 9 units down. Point C represents the Natural History Museum, and is located at approximately 8 units across and 8 units down. Point D represents the Smithsonian, and is located at 10 units across and 10 units down. Point E represents the National Portrait Gallery, and is located at 12 units across and 3 units down. Point F represents the National Gallery of Art, and is located at 14 units across and 8 units down. A scale shows 200 feet and 200 meters.
Find the length between landmark B and F. Round the answer to the nearest hundredth, if necessary.
(1 point)
units
A map shows a grid 17 units across and 12 units high, superimposed over shapes that represent streets and buildings. A key lists buildings located in Washington D.C. that correspond to points on the grid. Point A represents the White House. It is located at 4 units across from the left, and 3 units down from the top. Point B represents the Washington Monument, located at 5 units across and 9 units down. Point C represents the Natural History Museum, and is located at approximately 8 units across and 8 units down. Point D represents the Smithsonian, and is located at 10 units across and 10 units down. Point E represents the National Portrait Gallery, and is located at 12 units across and 3 units down. Point F represents the National Gallery of Art, and is located at 14 units across and 8 units down. A scale shows 200 feet and 200 meters.
Find the length between landmark B and F. Round the answer to the nearest hundredth, if necessary.
(1 point)
units
To find the distance between landmark B and landmark F, we can use the coordinates given in the image.
Landmark B is located at 5 units across and 9 units down. Landmark F is located at 14 units across and 8 units down.
To find the horizontal distance, we can subtract the x-coordinates of the two landmarks:
14 - 5 = 9 units
To find the vertical distance, we can subtract the y-coordinates of the two landmarks:
8 - 9 = -1 unit
Since the vertical distance is negative, we can consider the absolute value of it:
|-1| = 1 unit
Using the Pythagorean theorem, we can calculate the distance between the two landmarks:
distance = √(horizontal distance)^2 + (vertical distance)^2
distance = √(9)^2 + (1)^2
distance = √81 + 1
distance = √82
Rounding to the nearest hundredth, the length between landmark B and F is approximately 9.06 units.
Landmark B is located at 5 units across and 9 units down. Landmark F is located at 14 units across and 8 units down.
To find the horizontal distance, we can subtract the x-coordinates of the two landmarks:
14 - 5 = 9 units
To find the vertical distance, we can subtract the y-coordinates of the two landmarks:
8 - 9 = -1 unit
Since the vertical distance is negative, we can consider the absolute value of it:
|-1| = 1 unit
Using the Pythagorean theorem, we can calculate the distance between the two landmarks:
distance = √(horizontal distance)^2 + (vertical distance)^2
distance = √(9)^2 + (1)^2
distance = √81 + 1
distance = √82
Rounding to the nearest hundredth, the length between landmark B and F is approximately 9.06 units.
Use the image to answer the question.
A graph shows four quadrants with the x-axis and y-axis both ranging from negative 10 to positive 10 in increments of 1. Unlabeled points are plotted at left parenthesis negative 6 comma 8 right parenthesis, left parenthesis 4 comma 8 right parenthesis, left parenthesis 4 comma negative 3 right parenthesis, and left parenthesis negative 6 comma negative 3 right parenthesis. A straight line joins the four points forming a rectangle.
What is the length of the diagonal of the rectangle? Round your answer to the nearest hundredth, if necessary.
(1 point)
units
A graph shows four quadrants with the x-axis and y-axis both ranging from negative 10 to positive 10 in increments of 1. Unlabeled points are plotted at left parenthesis negative 6 comma 8 right parenthesis, left parenthesis 4 comma 8 right parenthesis, left parenthesis 4 comma negative 3 right parenthesis, and left parenthesis negative 6 comma negative 3 right parenthesis. A straight line joins the four points forming a rectangle.
What is the length of the diagonal of the rectangle? Round your answer to the nearest hundredth, if necessary.
(1 point)
units
To find the length of the diagonal of the rectangle, we can use the distance formula.
The two points that would form the diagonal of the rectangle are (-6, 8) and (4, -3).
Using the distance formula:
distance = √((x2 - x1)^2 + (y2 - y1)^2)
Substituting the coordinates of the two points:
distance = √((4 - (-6))^2 + (-3 - 8)^2)
distance = √((10)^2 + (-11)^2)
distance = √(100 + 121)
distance = √221
Rounding to the nearest hundredth, the length of the diagonal of the rectangle is approximately 14.87 units.
The two points that would form the diagonal of the rectangle are (-6, 8) and (4, -3).
Using the distance formula:
distance = √((x2 - x1)^2 + (y2 - y1)^2)
Substituting the coordinates of the two points:
distance = √((4 - (-6))^2 + (-3 - 8)^2)
distance = √((10)^2 + (-11)^2)
distance = √(100 + 121)
distance = √221
Rounding to the nearest hundredth, the length of the diagonal of the rectangle is approximately 14.87 units.
Find the distance between (2, 3) and (−4, −9). Round your answer to the nearest hundredth, if necessary.(1 point)
units
units
To find the distance between (2, 3) and (-4, -9), we can use the distance formula.
The distance formula is given by:
distance = √((x2 - x1)^2 + (y2 - y1)^2)
Substituting the coordinates of the two points:
distance = √((-4 -2)^2 + (-9 -3)^2)
distance = √((-6)^2 + (-12)^2)
distance = √(36 + 144)
distance = √180
Rounding to the nearest hundredth, the distance between (2, 3) and (-4, -9) is approximately 13.42 units.
The distance formula is given by:
distance = √((x2 - x1)^2 + (y2 - y1)^2)
Substituting the coordinates of the two points:
distance = √((-4 -2)^2 + (-9 -3)^2)
distance = √((-6)^2 + (-12)^2)
distance = √(36 + 144)
distance = √180
Rounding to the nearest hundredth, the distance between (2, 3) and (-4, -9) is approximately 13.42 units.
Find the distance between (−8, −3) and (−2, −5). Round your answer to the nearest hundredth, if necessary.(1 point)
units
units
To find the distance between (-8, -3) and (-2, -5), we can use the distance formula.
The distance formula is given by:
distance = √((x2 - x1)^2 + (y2 - y1)^2)
Substituting the coordinates of the two points:
distance = √((-2 - (-8))^2 + (-5 - (-3))^2)
distance = √((6)^2 + (-2)^2)
distance = √(36 + 4)
distance = √40
Rounding to the nearest hundredth, the distance between (-8, -3) and (-2, -5) is approximately 6.32 units.
The distance formula is given by:
distance = √((x2 - x1)^2 + (y2 - y1)^2)
Substituting the coordinates of the two points:
distance = √((-2 - (-8))^2 + (-5 - (-3))^2)
distance = √((6)^2 + (-2)^2)
distance = √(36 + 4)
distance = √40
Rounding to the nearest hundredth, the distance between (-8, -3) and (-2, -5) is approximately 6.32 units.