Ask a New Question
Menu

Use the image to answer the question.

A line segment on a coordinate plane. Both the x-and y-axes range from negative 3 to 4 in unit increments. The line segment descends from upper A on the top left to upper B on the bottom right.

Find midpoint M
of the line segment with endpoints A(−1.4,2.5)
and B(2.6,−1.5)
. Enter both responses as a decimal value to the tenth place.

(1 point)
The midpoint of segment AB¯¯¯¯¯¯¯¯
is (
,
).
Remaining Attempts : 3
Skip to navigation

1 answer

To find the midpoint \( M \) of the line segment with endpoints \( A(-1.4, 2.5) \) and \( B(2.6, -1.5) \), you can use the midpoint formula:

\[ M(x, y) = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \]

where \( (x_1, y_1) \) are the coordinates of point \( A \) and \( (x_2, y_2) \) are the coordinates of point \( B \).

Substituting in the values:

  • \( x_1 = -1.4 \)
  • \( y_1 = 2.5 \)
  • \( x_2 = 2.6 \)
  • \( y_2 = -1.5 \)

Calculating the x-coordinate of the midpoint:

\[ M_x = \frac{-1.4 + 2.6}{2} = \frac{1.2}{2} = 0.6 \]

Calculating the y-coordinate of the midpoint:

\[ M_y = \frac{2.5 + (-1.5)}{2} = \frac{1.0}{2} = 0.5 \]

Thus, the midpoint \( M \) of segment \( AB \) is:

\[ M(0.6, 0.5) \]

The final answer, rounded to the tenth place, is:

The midpoint of segment \( AB \) is \( (0.6, 0.5) \).