Use the image to answer the question.

A line is plotted on a coordinate plane. The line begins in quadrant 2 sloping downward from left to right, passes through quadrant 1, and descends through quadrant 4.

Identify the y-intercept.

(1 point)
there is no plot point just a line running through, although the line dows meet head-on with the points 4,3 and 2,6 if the y axis coordinate goes before x

1 answer

To identify the y-intercept of a line plotted on a coordinate plane, we need to find the point where the line crosses the y-axis. The y-intercept is the value of \( y \) when \( x = 0 \).

Based on your description of the line sloping downwards and passing through quadrants 2, 1, and 4, the line will intersect the y-axis at some point above the x-axis.

From your mention of points (4, 3) and (2, 6):

  • The first point (4, 3) means when \( x = 4 \), \( y = 3 \).
  • The second point (2, 6) means when \( x = 2 \), \( y = 6 \).

Even though you haven't provided the exact coordinates of the y-intercept, we can determine that the line slopes downward between the two points mentioned, which means that the y-intercept must be above both of those points.

If no specific intersection point has been given for the y-axis in your description, we cannot definitively state the y-intercept coordinates. However, it most likely lies at a positive value of \( y \) above 6 when \( x = 0 \), based on the downward slope of the line. If you need a precise value or if there's a specific point highlighted in the image, please provide that information.

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