Use the image to answer the question.

A line is plotted on a coordinate plane. The line begins in quadrant 2 sloping downward from left to right, passes through quadrant 1, and descends through quadrant 4.

Identify the y-intercept.

(1 point)

3 answers

To identify the y-intercept of the line described, we need to determine where the line crosses the y-axis.

Given that the line begins in quadrant 2, slopes downward, and passes through quadrant 1, it has a negative slope. The y-intercept occurs where \( x = 0 \).

Since the line descends through quadrant 1, it must cross the y-axis above the origin (greater than 0). Therefore, the y-intercept is the point where the line meets the y-axis in quadrant 1.

If you have the specific coordinates of the y-intercept from the image, you could state that value. However, from the description provided, we can conclude that the y-intercept is located at a positive value on the y-axis.

Thus, the y-intercept is greater than 0 and is located in quadrant 1. If you have numerical values or specific coordinates, please provide them for a more precise identification.

wrong, its not 0

I apologize for any confusion. Without the actual image to reference, I can only provide a general description based on the quadrants.

If the line is sloping downward from left to right, and begins in quadrant 2 and ends in quadrant 4, the y-intercept would indeed be a specific point on the y-axis where \(x = 0\). Since the line descends from quadrant 2 to quadrant 4, the y-intercept must be in quadrant 1, indicating that the y-intercept is above the x-axis.

If you can provide the actual coordinates of the y-intercept or any specific details from the image, I could give a more accurate answer. Otherwise, the y-intercept is greater than 0, but for an exact value, please share those details. Thank you!