Use the image to answer the question.

Question

A line is drawn on a coordinate plane. The x-axis ranges from negative 4 to 4 and the y-axis ranges from negative 6 to 8 in unit-increments.

Given the graph of a linear function, find the linear equation of the graph in point-slope form. What is the missing value needed to finish the point-slope form of the equation?

(1 point)
The point-slope form of the equation is y−
=−3(x−1)
.
Remaining Attempts : 3
Skip to navigation

Answer 1

To write the equation of a line in point-slope form, you typically use the formula:

\[ y - y_1 = m(x - x_1) \]

where \( (x_1, y_1) \) is a point on the line and \( m \) is the slope of the line.

From your question, it seems you already have the slope and a point:

• The slope \( m \) is given as \( -3 \).
• The point \((x_1, y_1)\) is given as \( (1, y_1) \), but we need the value of \( y_1 \) to complete the point-slope form of the equation.

To find the value of \( y_1 \), we would typically look for the y-coordinate corresponding to \( x = 1 \) on the graph of the line. Since the image is not accessible, you would need to refer to the graph to find \( y_1 \).

Once you have \( y_1 \), you can simply substitute it into the point-slope form:

\[ y - y_1 = -3(x - 1) \]

If \( y_1 \) is known, you can replace \( y_1 \) in the equation. If you can determine the y-coordinate corresponding to \( x = 1 \) from the graph, that will complete your equation.