Question

Use the image to answer the question.

A line is drawn on a coordinate plane. The x-axis ranges from negative 4 to 4 and the y-axis ranges from negative 6 to 8 in unit-increments.

Given the graph of a linear function, find the linear equation of the graph in point-slope form. What is the missing value needed to finish the point-slope form of the equation?

(1 point)
The point-slope form of the equation is y−
=−3(x−1)
.
Remaining Attempts : 3

Answer 1

To find the linear equation in point-slope form, we can use the point-slope formula, which is given as:

\[
y - y_1 = m(x - x_1)
\]

Where \( (x_1, y_1) \) is a point on the line, and \( m \) is the slope of the line.

From your input, it appears you already have:

\[
y - \text{missing value} = -3(x - 1)
\]

In this case, \( m = -3 \) and \( (x_1, y_1) = (1, \text{missing value}) \).

To complete the point-slope form, we need the value of \( y_1 \).

1. Identify the point on the graph where \( x = 1 \) (the value you have).
2. From the graph, determine the corresponding \( y \)-value when \( x = 1 \).

If you know the point on the graph corresponding to \( x = 1 \), simply substitute this \( y \)-value as \( y_1 \).

Once you have \( y_1 \), the missing value in your equation can be filled in.

For example, if you determine from the graph that when \( x = 1 \), \( y = 2 \), then the missing value would be 2, and the complete equation would be:

\[
y - 2 = -3(x - 1)
\]

Since I am unable to see the image, you would need to provide either the \( y \)-coordinate that corresponds with \( x = 1 \) or describe the graph further to determine the missing value.