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Question

A horizontal rectangle is shown with two small right triangles extending above and below on the left side of the rectangle. The overall length of the horizontal rectangle is 8 feet, and the width is 4 feet. The two right triangles extend outward top and bottom from the left width side of the rectangle by 2 feet each. The sides of the triangles that are common to the length of the rectangle are labeled as 3 feet.

Mr. Ming’s second grade class is making a mural to celebrate the completion of their unit on astronomy. The image of the spaceship will be central to the mural. What is the area of the spaceship?

(1 point)
Responses

30 ft.2
30 ft. squared

35 ft.2
35 ft. squared

32 ft.2
32 ft. squared

38 ft.2
38 ft. squared
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Answer 1

To find the area of the spaceship, we need to find the total area of the rectangle and then subtract the areas of the two right triangles.

Area of the rectangle = length x width
Area of the rectangle = 8 ft x 4 ft = 32 ft^2

Area of one right triangle = (1/2) base x height
Area of one right triangle = (1/2) x 2 ft x 3 ft = 3 ft^2

So, the total area of both right triangles = 2 x 3 ft^2 = 6 ft^2

Therefore, the area of the spaceship (rectangle minus triangles) = 32 ft^2 - 6 ft^2 = 26 ft^2

Therefore, the area of the spaceship is 26 ft^2

So the correct answer is 26 ft^2