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A graphed function starting on the x axis has an arrow at the other end passes through three points on a coordinate plane. The x-axis ranges from negative 9 to 9 in unit increments and the y-axis ranges from negative 11 to 11 in unit increments.
Which table shows that y=−f(x)
results in a reflection over the x-axis?
(1 point)
Responses
x −f(x)
−2
0
−3
−1
−6
−2
x f left parenthesis x right parenthesis negative 2 0 negative 3 negative 1 negative 6 negative 2
x −f(x)
2 0
3 −1
6 −2
x f left parenthesis x right parenthesis 2 0 3 negative 1 6 negative 2
x −f(x)
−2
0
−3
1
−6
2
x f left parenthesis x right parenthesis negative 2 0 negative 3 1 negative 6 2
x −f(x)
2 0
3 1
6 2
A graphed function starting on the x axis has an arrow at the other end passes through three points on a coordinate plane. The x-axis ranges from negative 9 to 9 in unit increments and the y-axis ranges from negative 11 to 11 in unit increments.
Which table shows that y=−f(x)
results in a reflection over the x-axis?
(1 point)
Responses
x −f(x)
−2
0
−3
−1
−6
−2
x f left parenthesis x right parenthesis negative 2 0 negative 3 negative 1 negative 6 negative 2
x −f(x)
2 0
3 −1
6 −2
x f left parenthesis x right parenthesis 2 0 3 negative 1 6 negative 2
x −f(x)
−2
0
−3
1
−6
2
x f left parenthesis x right parenthesis negative 2 0 negative 3 1 negative 6 2
x −f(x)
2 0
3 1
6 2
Answers
Answered by
GPT-4o mini
To find the correct table that shows \( y = -f(x) \), we need to consider how the values of \( f(x) \) are transformed by multiplying them by -1. This transformation reflects the graph over the x-axis.
The values of \( y = -f(x) \) should be the negative of the corresponding values of \( f(x) \).
Let's analyze the given tables:
1. **First Table:**
- \( x \) | \( -f(x) \)
- -2 | ?
- 0 | ?
- -3 | ?
- -1 | ?
- -6 | ?
- -2 | ?
Here the transformation is not clear since \( f(x) \) values are not provided.
2. **Second Table:**
- \( x \) | \( -f(x) \)
- 2 | 0
- 3 | -1
- 6 | -2
Here, potential \( f(x) \) values could be:
- \( f(2) = 0 \)
- \( f(3) = 1 \) (since -f(3) = -1)
- \( f(6) = 2 \) (since -f(6) = -2)
3. **Third Table:**
- \( x \) | \( -f(x) \)
- -2 | ?
- 0 | ?
- -3 | 1
- -6 | 2
Here also \( f(x) \) values are uncertain.
4. **Fourth Table:**
- \( x \) | \( -f(x) \)
- 2 | 0
- 3 | 1
- 6 | 2
Here, potential \( f(x) \) values could be:
- \( f(2) = 0 \) (since -f(2) = 0)
- \( f(3) = -1 \) (since -f(3) = 1)
- \( f(6) = -2 \) (since -f(6) = 2)
After analyzing the tables, it seems that the second table correctly shows the relationship of \( y = -f(x) \) because the \( -f(x) \) values are indeed the negatives of reasonable \( f(x) \) values.
Thus, the correct answer is the **second table**.
The values of \( y = -f(x) \) should be the negative of the corresponding values of \( f(x) \).
Let's analyze the given tables:
1. **First Table:**
- \( x \) | \( -f(x) \)
- -2 | ?
- 0 | ?
- -3 | ?
- -1 | ?
- -6 | ?
- -2 | ?
Here the transformation is not clear since \( f(x) \) values are not provided.
2. **Second Table:**
- \( x \) | \( -f(x) \)
- 2 | 0
- 3 | -1
- 6 | -2
Here, potential \( f(x) \) values could be:
- \( f(2) = 0 \)
- \( f(3) = 1 \) (since -f(3) = -1)
- \( f(6) = 2 \) (since -f(6) = -2)
3. **Third Table:**
- \( x \) | \( -f(x) \)
- -2 | ?
- 0 | ?
- -3 | 1
- -6 | 2
Here also \( f(x) \) values are uncertain.
4. **Fourth Table:**
- \( x \) | \( -f(x) \)
- 2 | 0
- 3 | 1
- 6 | 2
Here, potential \( f(x) \) values could be:
- \( f(2) = 0 \) (since -f(2) = 0)
- \( f(3) = -1 \) (since -f(3) = 1)
- \( f(6) = -2 \) (since -f(6) = 2)
After analyzing the tables, it seems that the second table correctly shows the relationship of \( y = -f(x) \) because the \( -f(x) \) values are indeed the negatives of reasonable \( f(x) \) values.
Thus, the correct answer is the **second table**.
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