Use the image to answer the question.

A graph with the x-axis representing oranges ranging from 0 to 36 in increments of 3 and the y-axis representing dollars ranging from 0 to 20 in increments of 1 shows six plotted points, 3 each for option A and option B. Option A has the following points: left parenthesis 12 comma 5 right parenthesis; left parenthesis 24 comma 10 right parenthesis; and left parenthesis 36 comma 15 right parenthesis. Option B has the following points: left parenthesis 9 comma 6 right parenthesis; left parenthesis 18 comma 12 right parenthesis; and left parenthesis 27 comma 18 right parenthesis.

If someone plans to buy 36 oranges, which option will save them more money?

(1 point)
Responses

Option B, because the price is lower for the same number of oranges.
Option B, because the price is lower for the same number of oranges.

Option B, because the price is higher for the same number of oranges.
Option B, because the price is higher for the same number of oranges.

Option A, because the price is higher for the same number of oranges.
Option A, because the price is higher for the same number of oranges.

Option A, because the price is lower for the same number of oranges.
Option A, because the price is lower for the same number of oranges.
Skip to navigation

1 answer

To determine which option saves more money when buying 36 oranges, we need to look at the prices associated with that quantity for both options.

In the provided points:

  • For Option A at 36 oranges, the price is 15 dollars (point (36, 15)).
  • For Option B at 36 oranges, we don't have a direct point listed, but we can infer from the points given that the price for 36 oranges would likely be higher than the last price provided (27 oranges at 18 dollars), indicating it could be more than 18 dollars.

Since Option A charges 15 dollars for 36 oranges and Option B charges more than 18 dollars, Option A is clearly the cheaper choice.

Thus, the correct answer is: Option A, because the price is lower for the same number of oranges.