Use the image to answer the question.

A curve labeled p of x and five points on the curve are plotted on a coordinate plane. The curve begins on the x-axis sloping upward from left to right, passes through quadrant 2, and then rises through quadrant 1.

Compare the average rates of change for the graphed square root function p(x)=x+4−−−−√
and the cube root function f(x)=x+4−−−−√3
over the interval [−4,−3]
.

(1 point)
Responses

The functions have the same average rate of change of 1.
The functions have the same average rate of change of 1.

The functions have the same average rate of change of 0.
The functions have the same average rate of change of 0.

The square root function has the greater average rate of change.
The square root function has the greater average rate of change.

The cube root function has the greater average rate of change.

1 answer

To find the average rates of change of the functions \( p(x) = \sqrt{x + 4} \) and \( f(x) = \sqrt[3]{x + 4} \) over the interval \([-4, -3]\), we will calculate the average rate of change for both functions using the formula:

\[ \text{Average Rate of Change} = \frac{f(b) - f(a)}{b - a} \]

where \( a = -4 \) and \( b = -3 \).

  1. For the square root function \( p(x) = \sqrt{x + 4} \):

    \[ p(-4) = \sqrt{-4 + 4} = \sqrt{0} = 0 \] \[ p(-3) = \sqrt{-3 + 4} = \sqrt{1} = 1 \]

    Now calculate the average rate of change:

    \[ \text{Average Rate of Change} = \frac{p(-3) - p(-4)}{-3 - (-4)} = \frac{1 - 0}{-3 + 4} = \frac{1}{1} = 1 \]

  2. For the cube root function \( f(x) = \sqrt[3]{x + 4} \):

    \[ f(-4) = \sqrt[3]{-4 + 4} = \sqrt[3]{0} = 0 \] \[ f(-3) = \sqrt[3]{-3 + 4} = \sqrt[3]{1} = 1 \]

    Now calculate the average rate of change:

    \[ \text{Average Rate of Change} = \frac{f(-3) - f(-4)}{-3 - (-4)} = \frac{1 - 0}{-3 + 4} = \frac{1}{1} = 1 \]

Thus, for both functions, the average rates of change over the interval \([-4, -3]\) are equal to 1.

Based on this calculation, the correct response is:

The functions have the same average rate of change of 1.

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