To compare the average rates of change for the functions \( p(x) = \sqrt{x + 4} \) (square root function) and \( f(x) = \sqrt[3]{x + 4} \) (cube root function) over the interval \([-4, -3]\), we can use the formula for the average rate of change:
\[ \text{Average Rate of Change} = \frac{f(b) - f(a)}{b - a} \]
where \( a = -4 \) and \( b = -3 \).
For the square root function \( p(x) = \sqrt{x + 4} \):
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Calculate \( p(-4) \): \[ p(-4) = \sqrt{-4 + 4} = \sqrt{0} = 0 \]
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Calculate \( p(-3) \): \[ p(-3) = \sqrt{-3 + 4} = \sqrt{1} = 1 \]
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Now, calculate the average rate of change for \( p(x) \): \[ \text{Average Rate of Change for } p(x) = \frac{p(-3) - p(-4)}{-3 - (-4)} = \frac{1 - 0}{-3 + 4} = \frac{1}{1} = 1 \]
For the cube root function \( f(x) = \sqrt[3]{x + 4} \):
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Calculate \( f(-4) \): \[ f(-4) = \sqrt[3]{-4 + 4} = \sqrt[3]{0} = 0 \]
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Calculate \( f(-3) \): \[ f(-3) = \sqrt[3]{-3 + 4} = \sqrt[3]{1} = 1 \]
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Now, calculate the average rate of change for \( f(x) \): \[ \text{Average Rate of Change for } f(x) = \frac{f(-3) - f(-4)}{-3 - (-4)} = \frac{1 - 0}{-3 + 4} = \frac{1}{1} = 1 \]
Conclusion:
Both the square root function \( p(x) \) and the cube root function \( f(x) \) have the same average rate of change of 1 over the interval \([-4, -3]\).
The correct response is: The functions have the same average rate of change of 1.