Use the image to answer the question.

A curve and two labeled points on the curve are plotted in quadrant 1 of a coordinate plane.

Given the graph of the exponential equation, write the correct exponential equation for the graph.

(1 point)
Responses

y=2(32)x
y equals 2 left parenthesis Start Fraction 3 over 2 End Fraction right parenthesis superscript x baseline

y=3(23)x
y equals 3 left parenthesis Start Fraction 2 over 3 End Fraction right parenthesis superscript x baseline

y=3(32)x
y equals 3 left parenthesis Start Fraction 3 over 2 End Fraction right parenthesis superscript x baseline

y=32(3)x
y equals Start Fraction 3 over 2 End Fraction left parenthesis 3 right parenthesis superscript x baseline

1 answer

To identify the correct exponential equation from the given options, we typically need to know the base value and the initial value (y-intercept) of the curve from the graph.

Since I can't see the graph you've provided, I can't directly derive the equation. However, I can help you understand how to analyze the points on the curve to determine the equation:

  1. Identify the y-intercept: If the graph passes through a specific point, say \( (0, y_0) \), then \( y_0 \) is your initial value (the coefficient in front of the exponential).

  2. Determine the base: Look for a second point on the curve. If you have two points—let’s say \( (x_1, y_1) \) and \( (x_2, y_2) \)—you can find the factor by which \( y \) increases as \( x \) increases. The base \( b \) can often be found using the formula: \[ b = \frac{y_2}{y_1} \text{ if } x_2 - x_1 = 1 \]

  3. Formulate the equation: The general form of an exponential function is \( y = a \cdot b^x \), where \( a \) is the initial value and \( b \) is the base.

Based on the structure of provided responses, you can substitute the identified \( a \) and \( b \) into the format \( y = a \cdot b^x \) to choose the correct option.

If you can provide more information about the specific points located on the graph, I would be able to assist you in narrowing down the correct option.