To determine the correct piecewise function corresponding to the two rays on the coordinate plane, we need to analyze the characteristics of each ray based on the descriptions you've provided.
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The first ray has an open endpoint, which means it does not include that endpoint in its function definition. This suggests that the function might involve the constraint \( x > 0 \) for that part of the piecewise function.
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The second ray starts from a closed endpoint, indicating that this part is included in the function. Therefore, it would use \( x \geq 0 \) for its definition.
Based on this analysis, the piecewise function must define the following:
- For the ray starting from the open endpoint (let’s say it is represented by a constant value \(-2\)), it applies when \( x > 0 \).
- For the ray with the closed endpoint (assuming it’s represented by a constant value \(3\)), it applies when \( x \leq 0 \).
So we can write the piecewise function as:
\[ y = \begin{cases} -2, & x > 0 \ 3, & x \leq 0 \end{cases} \]
Looking at the options provided in your question, we can see that the correct piecewise function matching our conclusion is:
y={−2, x>0 \ 3, x≤0}
Final answer: y={−2, x>0 \ 3, x≤0}